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3x^2-54x=-204
We move all terms to the left:
3x^2-54x-(-204)=0
We add all the numbers together, and all the variables
3x^2-54x+204=0
a = 3; b = -54; c = +204;
Δ = b2-4ac
Δ = -542-4·3·204
Δ = 468
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{468}=\sqrt{36*13}=\sqrt{36}*\sqrt{13}=6\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-6\sqrt{13}}{2*3}=\frac{54-6\sqrt{13}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+6\sqrt{13}}{2*3}=\frac{54+6\sqrt{13}}{6} $
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